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Proof step 7 from proof newref-in-01 (conclusion)

⊦ newref(r, st) ∧ r0 ∈ st → r ≠ r0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ newref(r, st) ↔ r ≠ jvmref ∧ (∀ rk. rk ∈ st → rk .ref ≠ r)
Proof step 6:
r0 ∈ st, ∀ rk. rk ∈ st → rk .ref ≠ r0 ⊦ r0 = jvmref

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]