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Proof step 4 from proof newref-in-03 (
previous step
)
r0 -- sk ∈ st, r0 ∈ st, ∀ rk. rk ∈ st → rk .ref ≠ r0 ⊦ r0 = jvmref
Heuristic quantifier closing applied rule all left
And closed the goal!
Rule argument
[EXRARG : pos: left 3, [QUANTTERMLIST : (r0 -- sk)]]
Additional information
[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (r -- sk) .ref = r])], [EXTRATERMS : (r0 -- sk)]]