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Proof step 5 from proof newref-newref-subset (previous step)

st0 ⊆ st ⊦ newref(newref(st), st0), newref(st) ∈ st0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ newref(r, st) ↔ r ≠ jvmref ∧ ¬ r ∈ st
Proof step 4:
⊦ newref(st) ≠ jvmref

Rule argument

[crewrite-arg: newref-def, F, [st, r] → [st0, newref(st)]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st0, newref(st))]]