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Proof step 22 from proof newref-same (previous step)

r ∈ st → maxref(st) ∈ st ∧ (∀ r. r ∈ st → ¬ maxref(st) < r), r ∈ st, ∀ r. r ∈ st ↔ r ∈ st0 ⊦ next(maxref(st)) = next(maxref(st0))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 21:
r ∈ st, maxref(st) ∈ st, ∀ r. r ∈ st ↔ r ∈ st0, ∀ r. r ∈ st → ¬ maxref(st) < r ⊦ next(maxref(st)) = next(maxref(st0))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]