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Proof step 2 from proof newref-subset (previous step)

newref(st0) ∈ st, ∀ r. r ∈ st → r ∈ st0 ⊦

Heuristic quantifier closing applied rule all left

And obtained the following new goals

Rule argument

[EXRARG : pos: left 2, [QUANTTERMLIST : (newref(st0))]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (newref(st0))]]