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Proof step 5 from proof newreflist-dups-01 (previous step)

newref(st) ∈ newref_list(m, st[newref(st) -- 0 ', noval]), ∀ st. ¬ dups(newref_list(m, st)) ⊦ dups(newref_list(m, st[newref(st) -- 0 ', noval]))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ r ∈ st → ¬ r ∈ newref_list(n, st)
Proof step 4:
⊦ r ∈ st[r0 -- sk, val] ↔ r = r0 ∨ r ∈ st

Rule argument

[crewrite-arg: newrefs-in , F , [st, n, r] → [st[newref(st) -- 0 ', noval], m, newref(st)] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st[newref(st) -- 0 ', noval], m, newref(st))]]