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Proof step 7 from proof newreflist-dups-01 (previous step)

∀ st. ¬ dups(newref_list(m, st)) ⊦ ¬ newref(st) ∈ newref_list(m, st[newref(st) -- 0 ', noval]) ∧ ¬ dups(newref_list(m, st[newref(st) -- 0 ', noval]))

User applied rule all left

And obtained the following new goals

Proof step 6:
¬ dups(newref_list(m, st[newref(st) -- 0 ', noval])), ∀ st. ¬ dups(newref_list(m, st)) ⊦ ¬ newref(st) ∈ newref_list(m, st[newref(st) -- 0 ', noval]) ∧ ¬ dups(newref_list(m, st[newref(st) -- 0 ', noval]))

Rule argument

[EXRARG : pos: left 1, [extquanttermlist: (st[newref(st) -- 0 ', noval]) abort:F , discard:F , computed:T ]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st[newref(st) -- 0 ', noval])]]