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Proof step 4 from proof newrefs-01 (conclusion)

⊦ is_newref_list(r ' + r0 ', st) ↔ r ≠ r0 ∧ newref(r, st) ∧ newref(r0, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ newref(r, st) ↔ r ≠ jvmref ∧ (∀ rk. rk ∈ st → rk .ref ≠ r)
Proof step 2:
⊦ is_newref_list(r ', st) ↔ newref(r, st)
Proof step 3:
⊦ is_newref_list(r ' + refs, st) ↔ ¬ ¬ (¬ r ∈ refs ∧ newref(r, st) ∧ is_newref_list(refs, st))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r ∈ r0 ' ↔ r = r0], [CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1])]]