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Proof step 10 from proof newrefs-butlast-01 (previous step)

¬ newref_list(1 + m, st[newref(st) -- 0 ', noval]) ≠ [], ∀ st. newref_list(m + 1, st) .butlast = newref_list(m, st) ⊦ (newref(st) ' + newref_list(1 + m, st[newref(st) -- 0 ', noval])) .butlast = newref(st) ' + newref_list(m, st[newref(st) -- 0 ', noval])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
⊦ newref_list(n, st) = [] ↔ n = 0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ m + n = n + m], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ m + 1 ≠ 0])]]