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Proof step 5 from proof newrefs-empty (previous step)

newref_list(m + 1, st) = [], ∀ st. newref_list(m, st) = [] ↔ m = 0 ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ newref_list(n + 1, st) = newref(st) + newref_list(n, st[newref(st) -- 0 ', noval])

Rule argument

[crewrite-arg: newrefs-succ, F, [st, n] → [st, m]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r + refs = r ' + refs], [CSIMPSEQ : ⊦ ¬ refs + refs0 ≠ [] ↔ refs = [] ∧ refs0 = []], [CSIMPSEQ : ⊦ r ' ≠ []], [CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1])], [EXTRATERMS : (st, m)]]