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Proof step 7 from proof newrefs-in (previous step)

r ∈ st, r ∈ newref_list(m, st[newref(st) -- 0 ', noval]), ∀ r0, st0. ¬ r0 ∈ st0 ∨ ¬ r0 ∈ newref_list(m, st0) ⊦ r = newref(st)

Heuristic quantifier closing applied rule all left

And obtained the following new goals

Proof step 6:
⊦ r ∈ st[r0 -- sk, val] ↔ r = r0 ∨ r ∈ st

Rule argument

[EXRARG : pos: left 3, [QUANTTERMLIST : (r, st[newref(st) -- 0 ', noval])]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r, st[newref(st) -- 0 ', noval])]]