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Proof step 27 from proof newrefs-last-01 (previous step)

∀ st0. ¬ (newref(st0) ' + newref_list(m, st0[newref(st0) -- 0 ', noval])) .last ∈ newref_list(m, st0) ⊦ ¬ newref_list(2 + m, st) .last ∈ newref_list(m, st[newref(st) -- 0 ', noval]) ∧ newref_list(2 + m, st) .last ≠ newref(st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ 0 < n → newref_list(n, st) = newref(st) + newref_list(n -1, st[newref(st) -- 0 ', noval])
Proof step 26:
0 < 2 + m, ∀ st0. ¬ (newref(st0) ' + newref_list(m, st0[newref(st0) -- 0 ', noval])) .last ∈ newref_list(m, st0) ⊦ ¬ (newref(st) + newref_list((2 + m) -1, st[newref(st) -- 0 ', noval])) .last ∈ newref_list(m, st[newref(st) -- 0 ', noval]) ∧ (newref(st) + newref_list((2 + m) -1, st[newref(st) -- 0 ', noval])) .last ≠ newref(st)

Rule argument

[crewrite-arg: newrefs-rec-01, F, [st, n] → [st, 2 + m]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ 0 < n ↔ n ≠ 0], [CSIMPSEQ : ⊦ m + n = 0 ↔ m = 0 ∧ n = 0], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ m + n = n + m])], [EXTRATERMS : (st, 2 + m)]]