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Proof step 6 from proof newrefs-lastn (previous step)

n ≤ # refs, ∀ r0. r0 ∈ refs → r0 ≠ jvmref ∧ (∀ rk. rk ∈ st → rk .ref ≠ r0) ⊦ dups(refs), ¬ dups(lastn(n, refs)) ∧ (r ∈ lastn(n, refs) → newref(r, st))

User applied rule all left

And obtained the following new goals

Proof step 5:
n ≤ # refs, r ∈ refs → r ≠ jvmref ∧ (∀ rk. rk ∈ st → rk .ref ≠ r), ∀ r0. r0 ∈ refs → r0 ≠ jvmref ∧ (∀ rk. rk ∈ st → rk .ref ≠ r0) ⊦ dups(refs), ¬ dups(lastn(n, refs)) ∧ (r ∈ lastn(n, refs) → newref(r, st))

Rule argument

[EXRARG : pos: left 2, [extquanttermlist: (r)abort:F, discard:F, computed:F]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r)]]