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Proof step 4 from proof newrefs-length (previous step)

∀ st. # newref_list(m, st) = m ⊦ # newref_list(m +1, st) = m +1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ newref_list(n + 1, st) = newref(st) + newref_list(n, st[newref(st) -- 0 ', noval])
Proof step 3:
∀ st. # newref_list(m, st) = m ⊦ # newref_list(m, st[newref(st) -- 0 ', noval]) = m

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ m + n = m + n0 ↔ n = n0], [CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ # r ' = 0 +1], [CSIMPSEQ : ⊦ # (refs + refs0) = # refs + # refs0], [CSIMPSEQ : ⊦ m + n = n + m], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ r + refs = r ' + refs], [CSIMPSEQ : ⊦ m +1 = m + 1])]]