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Proof step 24 from proof newrefs-new-01 (previous step)

¬ r ∈ st[newref(st) -- 0 ', noval], r ∈ newref_list(m, st[newref(st) -- 0 ', noval]), ∀ st. is_newref_list(newref_list(m, st), st), ∀ r. r ∈ newref_list(m, st[newref(st) -- 0 ', noval]) → r ≠ newref(st) ∧ r ≠ jvmref ∧ (∀ rk. rk ∈ st → rk .ref ≠ r) ⊦ dups(newref_list(m, st[newref(st) -- 0 ', noval])), newref(r, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
⊦ r ∈ st[r0 -- sk, val] ↔ r = r0 ∨ r ∈ st
Proof step 23:
r ∈ newref_list(m, st[newref(st) -- 0 ', noval]), ∀ st. is_newref_list(newref_list(m, st), st), ∀ r. r ∈ newref_list(m, st[newref(st) -- 0 ', noval]) → r ≠ newref(st) ∧ r ≠ jvmref ∧ (∀ rk. rk ∈ st → rk .ref ≠ r) ⊦ r = newref(st), dups(newref_list(m, st[newref(st) -- 0 ', noval])), newref(r, st), r ∈ st

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]