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Proof step 29 from proof newrefs-new-01 (previous step)

is_newref_list(newref_list(m, st[newref(st) -- 0 ', noval]), st[newref(st) -- 0 ', noval]), ∀ st. is_newref_list(newref_list(m, st), st) ⊦ is_newref_list(newref_list(m, st[newref(st) -- 0 ', noval]), st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ is_newref_list(refs, st) ↔ ¬ dups(refs) ∧ (∀ r. r ∈ refs → newref(r, st))
Proof step 28:
¬ dups(newref_list(m, st[newref(st) -- 0 ', noval])) ∧ (∀ r. r ∈ newref_list(m, st[newref(st) -- 0 ', noval]) → newref(r, st[newref(st) -- 0 ', noval])), ∀ st. is_newref_list(newref_list(m, st), st) ⊦ is_newref_list(newref_list(m, st[newref(st) -- 0 ', noval]), st)

Rule argument

[crewrite-arg: list_ok , F , [st, refs] → [st[newref(st) -- 0 ', noval], newref_list(m, st[newref(st) -- 0 ', noval])] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st[newref(st) -- 0 ', noval], newref_list(m, st[newref(st) -- 0 ', noval]))]]