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Proof step 4 from proof newrefs-rec-01 (previous step)

⊦ newref_list(n, st) = newref(st) ' + newref_list(n - 1, st[newref(st) -- 0 ', noval]), n = 0

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 3:
n = m + 1 ⊦ newref_list(n, st) = newref(st) ' + newref_list(m, st[newref(st) -- 0 ', noval]), n = 0

Rule argument

[speclemmaarg: n ≠ 0 ,m = n - 1 ↔ n = m + 1 ,[n, m] → [n, m] ,T ,nat , ,elim-pred-c ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1])], [EXTRATERMS : (n, m)]]