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Proof step 12 from proof newrefs-rec (previous step)

r0 ∈ st, r0 -- sk ∈ st, r0 ∈ refs, ∀ rk. rk ∈ st → rk .ref ≠ r0, ∀ rk. rk ∈ st → rk .ref ≠ r, ∀ r0. r0 ∈ refs → r0 ≠ jvmref ∧ (∀ rk. rk ∈ st → rk .ref ≠ r0) ⊦ r0 = jvmref, r = jvmref, r ∈ refs, dups(refs)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 4, [QUANTTERMLIST : (r0 -- sk)]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (r -- sk) .ref = r])], [EXTRATERMS : (r0 -- sk)]]