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Proof step 6 from proof newrefs-rec (previous step)

r0 ∈ refs, ∀ r0. r0 ∈ refs → r0 ≠ jvmref ∧ (∀ rk. rk ∈ st → rk .ref ≠ r0), ∀ rk. rk ∈ st → rk .ref ≠ r ⊦ r = jvmref, r ∈ refs, dups(refs), newref(r0, st)

User applied rule all left

And obtained the following new goals

Proof step 5:
⊦ newref(r, st) ↔ r ≠ jvmref ∧ (∀ rk. rk ∈ st → rk .ref ≠ r)

Rule argument

[EXRARG : pos: left 2, [extquanttermlist: (r0)abort:F, discard:F, computed:T]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r0)]]