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Proof step 5 from proof newrefs-rest (previous step)

(newref(st) + newref_list(n, st[newref(st) -- 0 ', noval])) .first ∈ (newref(st) + newref_list(n, st[newref(st) -- 0 ', noval])) .rest ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
newref(st) ∈ newref_list(n, st[newref(st) -- 0 ', noval]) ⊦

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (r ' + refs) .rest = refs], [CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ (r ' + refs) .first = r], [CSIMPSEQ : ⊦ r + refs = r ' + refs])]]