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Proof step 21 from proof newrefs-three (previous step)

¬ newref(st[newref(st) -- 0 ', noval][newref(st[newref(st) -- 0 ', noval]) -- 0 ', noval]) -- sk ∈ (st[newref(st) -- 0 ', noval][newref(st[newref(st) -- 0 ', noval]) -- 0 ', noval]) ⊦ ¬ newref(st[newref(st) -- 0 ', noval][newref(st[newref(st) -- 0 ', noval]) -- 0 ', noval]) -- sk ∈ st

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 14:
⊦ rk ≠ rk0 → (rk ∈ st[rk0, val] ↔ rk ∈ st)
Proof step 20:
¬ newref(st[newref(st) -- 0 ', noval][newref(st[newref(st) -- 0 ', noval]) -- 0 ', noval]) -- sk ≠ newref(st[newref(st) -- 0 ', noval]) -- 0 ', ¬ newref(st[newref(st) -- 0 ', noval][newref(st[newref(st) -- 0 ', noval]) -- 0 ', noval]) -- sk ∈ (st[newref(st) -- 0 ', noval][newref(st[newref(st) -- 0 ', noval]) -- 0 ', noval]) ⊦ ¬ newref(st[newref(st) -- 0 ', noval][newref(st[newref(st) -- 0 ', noval]) -- 0 ', noval]) -- sk ∈ st

Rule argument

[speclemmaarg: ,rk ≠ rk0 → (rk ∈ st[rk0, val] ↔ rk ∈ st) ,[val, rk0, st, rk] → [noval, newref(st[newref(st) -- 0 ', noval]) -- 0 ', st[newref(st) -- 0 ', noval], newref (st[newref(st) -- 0 ', noval] [newref(st[newref(st) -- 0 ', noval]) -- 0 ', noval ]) -- sk] ,F ,store ,javastore ,in-neq ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r -- sk = r0 -- sk0 ↔ ¬ ¬ (r = r0 ∧ sk = sk0)], [CSIMPSEQ : ⊦ rk ∈ st[rk0, val] ↔ rk = rk0 ∨ rk ∈ st])], [EXTRATERMS : (noval, newref(st[newref(st) -- 0 ', noval]) -- 0 ', st[newref(st) -- 0 ', noval], newref (st[newref(st) -- 0 ', noval] [newref(st[newref(st) -- 0 ', noval]) -- 0 ', noval ]) -- sk)]]