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Proof step 49 from proof newrefs-three (previous step)

newref(st) = newref(st[newref(st) -- 0 ', noval]) ⊦ ∃ r, r0, r1. newref_list(3, st) = r ' + r0 ' + r1 ' ∧ newref(r1, st) ∧ newref(r, st) ∧ newref(r0, st) ∧ r ≠ r0 ∧ r ≠ r1 ∧ r0 ≠ r1

User applied rule flip equation

And obtained the following new goals

Proof step 48:
newref(st[newref(st) -- 0 ', noval]) = newref(st) ⊦ ∃ r, r0, r1. newref_list(3, st) = r ' + r0 ' + r1 ' ∧ newref(r1, st) ∧ newref(r, st) ∧ newref(r0, st) ∧ r ≠ r0 ∧ r ≠ r1 ∧ r0 ≠ r1

Rule argument

[fmapos-arg: pos: left 1]

Additional information

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