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Proof step 63 from proof newrefs-three (previous step)

⊦ ∃ r, r0, r1. newref_list(3, st) = r ' + r0 ' + r1 ' ∧ newref(r1, st) ∧ newref(r, st) ∧ newref(r0, st) ∧ r ≠ r0 ∧ r ≠ r1 ∧ r0 ≠ r1

User applied rule exists right

And obtained the following new goals

Proof step 62:
⊦ newref_list(3, st) = newref(st) ' + newref(st[newref(st) -- 0 ', noval]) ' + newref(st[newref(st) -- 0 ', noval][newref(st[newref(st) -- 0 ', noval]) -- 0 ', noval]) ' ∧ newref(newref(st[newref(st) -- 0 ', noval][newref(st[newref(st) -- 0 ', noval]) -- 0 ', noval]), st) ∧ newref(newref(st), st) ∧ newref(newref(st[newref(st) -- 0 ', noval]), st) ∧ newref(st) ≠ newref(st[newref(st) -- 0 ', noval]) ∧ newref(st) ≠ newref(st[newref(st) -- 0 ', noval][newref(st[newref(st) -- 0 ', noval]) -- 0 ', noval]) ∧ newref(st[newref(st) -- 0 ', noval]) ≠ newref(st[newref(st) -- 0 ', noval][newref(st[newref(st) -- 0 ', noval]) -- 0 ', noval]), ∃ r, r0, r1. newref_list(3, st) = r ' + r0 ' + r1 ' ∧ newref(r1, st) ∧ newref(r, st) ∧ newref(r0, st) ∧ r ≠ r0 ∧ r ≠ r1 ∧ r0 ≠ r1

Rule argument

[EXRARG : pos: right 1, [extquanttermlist: (newref(st), newref(st[newref(st) -- 0 ', noval]), newref (st[newref(st) -- 0 ', noval] [ newref (st[newref(st) -- 0 ', noval]) -- 0 ', noval ])) abort:F , discard:F , computed:F ]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (newref(st), newref(st[newref(st) -- 0 ', noval]), newref (st[newref(st) -- 0 ', noval] [newref(st[newref(st) -- 0 ', noval]) -- 0 ', noval ]))]]