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Proof step 16 from proof newrefs-two (previous step)

newref(st[newref(st) -- 0 ', noval]) -- sk ∈ st, newref(st[newref(st) -- 0 ', noval]) ∈ st ⊦

User applied rule insert lemma

And obtained the following new goals

Proof step 9:
⊦ ¬ newref(st) ∈ st
Proof step 15:
¬ newref(st[newref(st) -- 0 ', noval]) ∈ st[newref(st) -- 0 ', noval], newref(st[newref(st) -- 0 ', noval]) -- sk ∈ st, newref(st[newref(st) -- 0 ', noval]) ∈ st ⊦

Rule argument

[LEMMAARG : newref-in, [st] → [st[newref(st) -- 0 ', noval]]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st[newref(st) -- 0 ', noval])]]