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Proof step 27 from proof newrefs-two (previous step)

⊦ newref_list(2, st) = newref(st) ' + newref(st[newref(st) -- 0 ', noval]) ' ∧ newref(newref(st), st) ∧ newref(newref(st[newref(st) -- 0 ', noval]), st) ∧ newref(st) ≠ newref(st[newref(st) -- 0 ', noval])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ newref(newref(st), st)
Proof step 26:
⊦ newref_list(2, st) = newref(st) ' + newref(st[newref(st) -- 0 ', noval]) ' ∧ newref(newref(st[newref(st) -- 0 ', noval]), st) ∧ newref(st) ≠ newref(st[newref(st) -- 0 ', noval])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]