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Proof step 4 from proof normal-out (previous step)

⊦ _mode ∈ st[_out, val] ∧ (st[_out, val][_mode]) = noval ↔ normalmode(st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ _mode ∈ st[_out, val] ∧ st[_mode] = noval ↔ normalmode(st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (st[_out, val][_mode]) = st[_mode]])]]