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Proof step 12 from proof put-last-rec (conclusion)

⊦ sks ≠ [] → st[r -- (sks + sk '), val] = st[st[r -- sks] .refval -- sk, val]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
⊦ sks = [], st[r -- (sks + sk '), val] = st[st[r -- sks] .refval -- sk, val]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]