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Proof step 3 from proof put-rec-01 (conclusion)

⊦ sks ≠ [] → st[r -- (sk ' + sks), val] = st[st[r -- sk] .refval -- sks, val]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ sks = [], st[r -- (sk ' + sks), val] = st[st[r -- sk] .refval -- sks, val]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]