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Proof step 9 from proof put-rkvs-absorb (previous step)

∀ val, st, rk, rkvs0. # rkvs0 < # (rkvs1 + (rk0 × val0) ') → (rk ∈ rkvs0 → (st[rk, val][rkvs0]) = st[rkvs0]) ⊦ (st[rk0, val][rkvs1][rk0, val0]) = (st[rkvs1][rk0, val0]), rk0 ∈ rkvs1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
⊦ ¬ rk ∈ rkvs → (st[rk, val][rkvs]) = (st[rkvs][rk, val])

Rule argument

[crewrite-arg: put-rkvs-switch , F , [rkvs, val, rk, st] → [rkvs1, val, rk0, st] ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (st[rk, val][rk, val0]) = st[rk, val0]])], [EXTRATERMS : (rkvs1, val, rk0, st)]]