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Proof step 5 from proof put-rkvs-last (conclusion)

⊦ rkvs ≠ [] → st[rkvs] = (st[rkvs .butlast][rkvs .last .1, rkvs .last .2])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]