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Proof step 8 from proof put-rkvs-switch (previous step)

∀ val, rk, st, rkvs0. # rkvs0 < # (rkvs1 + (rk0 × val0) ') → (true → (st[rk, val][rkvs0]) = (st[rkvs0][rk, val]) ∨ rk ∈ rkvs0) ⊦ (st[rk, val][rkvs1][rk0, val0]) = (st[rkvs1][rk0, val0][rk, val]), rk = rk0, rk ∈ rkvs1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ rk ≠ rk0 → (st[rk0, val][rk, val0]) = (st[rk, val0][rk0, val])
Proof step 7:
rk ≠ rk0, ∀ val, rk, st, rkvs0. # rkvs0 < # (rkvs1 + (rk0 × val0) ') → (true → (st[rk, val][rkvs0]) = (st[rkvs0][rk, val]) ∨ rk ∈ rkvs0) ⊦ (st[rk, val][rkvs1][rk0, val0]) = (st[rkvs1][rk, val][rk0, val0]), rk = rk0, rk ∈ rkvs1

Rule argument

[speclemmaarg: ,rk ≠ rk0 → (st[rk0, val][rk, val0]) = (st[rk, val0][rk0, val]) ,[val0, rk, val, rk0, st] → [val, rk, val0, rk0, st[rkvs1]] ,F ,store ,javastore-ostorea ,rew ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (val, rk, val0, rk0, st[rkvs1])]]