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Proof step 19 from proof refin-del (previous step)

r ∈ st ⊦ r = r1, ∃ sk. r -- sk ∈ st

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

[crewrite-arg: instore, F, [st, r] → [st, r]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, r)]]