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Proof step 25 from proof stsubset-new (conclusion)

⊦ newref(r, st) → (st ⊆ st0[r -- sk, val] ↔ st ⊆ st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ newref(r, st) ↔ r ≠ jvmref ∧ (∀ rk. rk ∈ st → rk .ref ≠ r)
Proof step 24:
∀ rk. rk ∈ st → rk .ref ≠ r ⊦ st ⊆ st0[r -- sk, val] ↔ st ⊆ st0, r = jvmref

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]