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Proof step 5 from proof stsubset-new (previous step)

r -- sk ∈ st, r ∈ st, ∀ rk. rk ∈ st → st[rk] = ((rk = r -- sk ⊃ st[r -- sk]; st0[rk])) ∧ rk ∈ st0[r -- sk, st[r -- sk]], ∀ rk. rk ∈ st → rk .ref ≠ r ⊦ r = jvmref, r -- sk ∈ st0 ∧ st[r -- sk] = st0[r -- sk]

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 4, [QUANTTERMLIST : (r -- sk)]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (r -- sk) .ref = r])], [EXTRATERMS : (r -- sk)]]