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Proof step 1 from proof subset-put-notin (
previous step
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⊦ st ⊆ st0[rk, val] ↔ st ⊆ st0 ∧ ¬ rk ∈ st ∨ rk × val ∈ st ∧ st -- rk ⊆ st0 -- rk
A spec-lemma