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Proof step 5 from proof uninit-03 (previous step)

∀ class1. initundone(class1, st) ⊦ jvmref -- mkfs(class, void_type, `initstate' .field) ' ∈ st ∧ st[jvmref -- mkfs(class, void_type, `initstate' .field) '] = initval(undone), ¬ jvmref -- mkfs(class, void_type, `initstate' .field) ' ∈ st ∧ _uninit ∈ st

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ initundone(class1, st) ↔ ¬ ¬ ( (jvmref -- mkfs(class1, void_type, `initstate' .field) ') × initval(undone) ∈ st ∨ ¬ jvmref -- mkfs(class1, void_type, `initstate' .field) ' ∈ st ∧ _uninit ∈ st)
Proof step 4:
∀ class0. ¬ jvmref -- mkfs(class0, void_type, `initstate' .field) ' ∈ st ∧ _uninit ∈ st ∨ jvmref -- mkfs(class0, void_type, `initstate' .field) ' ∈ st ∧ st[jvmref -- mkfs(class0, void_type, `initstate' .field) '] = initval(undone) ⊦ jvmref -- mkfs(class, void_type, `initstate' .field) ' ∈ st ∧ st[jvmref -- mkfs(class, void_type, `initstate' .field) '] = initval(undone), ¬ jvmref -- mkfs(class, void_type, `initstate' .field) ' ∈ st ∧ _uninit ∈ st

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ rk × val ∈ st ↔ rk ∈ st ∧ st[rk] = val])]]