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Proof step 3 from proof eqex-sym (
previous step
)
eqex(st, st0, r) ⊦ st0 -- r = st -- r
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 2
:
⊦ eqex(st, st0, r) ↔ st -- r = st0 -- r
Rule argument
[crewrite-arg: eqex, F, [r, st0, st] → [r, st0, st]]
Additional information
[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r, st0, st)]]