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Proof step 58 from proof eqex-tput (previous step)

st -- r = st0 -- r, eqex(st0[rk, val], st1, r), eqex(st0, st, r), eqex(st1, st0[rk, val], r) ⊦ st[rk, val] -- r = st1 -- r

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ eqex(st, st0, r) ↔ st -- r = st0 -- r
Proof step 57:
st -- r = st0 -- r, st0[rk, val] -- r = st1 -- r, eqex(st0, st, r), eqex(st1, st0[rk, val], r) ⊦ st[rk, val] -- r = st1 -- r

Rule argument

[crewrite-arg: eqex, F, [r, st0, st] → [r, st1, st0[rk, val]]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r, st1, st0[rk, val])]]