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Proof step 61 from proof eqex-tput (conclusion)

⊦ eqex(st, st0, r) ∧ eqex(st0[rk, val], st1, r) → eqex(st[rk, val], st1, r)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]