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Proof step 5 from proof eqex-trans (previous step)

st -- r = st0 -- r, eqex(st1, st0, r), eqex(st0, st, r), eqex(st0, st1, r) ⊦ st0 -- r = st1 -- r

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ eqex(st, st0, r) ↔ st -- r = st0 -- r

Rule argument

[crewrite-arg: eqex, F, [r, st0, st] → [r, st1, st0]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r, st1, st0)]]