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Proof step 9 from proof initdone-rec (previous step)

⊦ (∀ class0. class0 = class ∨ class0 ∈ classes → initdone(class0, st)) ↔ initdone(class, st) ∧ (∀ class. class ∈ classes → initdone(class, st))

User applied rule case distinction

And obtained the following new goals

Proof step 6:
∀ class0. class0 = class ∨ class0 ∈ classes → initdone(class0, st) ⊦ initdone(class, st) ∧ (∀ class. class ∈ classes → initdone(class, st))
Proof step 8:
initdone(class, st) ∧ (∀ class. class ∈ classes → initdone(class, st)) ⊦ ∀ class0. class0 = class ∨ class0 ∈ classes → initdone(class0, st)

Rule argument

[CASEDARG : pos: right 1, ()]

Additional information

[[CONCRETESIMPRULES : ()]]