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Proof step 3 from proof instore-inrefs-02 (
previous step
)
r ∈ st .refs ⊦ st = ∅, r ∈ st
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 2
:
⊦ r ∈ st .refs ↔ r ∈ st
Rule argument
[crewrite-arg: refs-def, F, [st, r] → [st, r]]
Additional information
[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, r)]]