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Proof step 4 from proof onlymod-put (previous step)

rk ∈ st ↔ rk ∈ st0, r ∈ st, r -- sk ∈ st, r -- _length ∈ st → st[r -- _length] = st0[r -- _length], r -- _type ∈ st → st[r -- _type] = st0[r -- _type], ∀ r0, sk. r0 ≠ r → st[r0 -- sk] = st0[r0 -- sk], ∀ rk. rk ∈ st ↔ rk ∈ st0 ⊦ sk = _type, sk = _length, st[r0 -- sk0] = st0[r0 -- sk0], r0 = r

User applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 6, [extquanttermlist: (r0, sk0)abort:F, discard:F, computed:T]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r0, sk0)]]