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Proof step 11 from proof refs-empty-01 (previous step)

∀ r. r ∈ st .refs ↔ r ∈ ∅ ⊦ st = ∅

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ r ∈ ∅])]]