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Proof step 8 from proof refs-empty-01 (previous step)

rk ∈ st, ∀ r. ¬ r ∈ st .refs ⊦

User applied rule all left

And obtained the following new goals

Proof step 7:
rk ∈ st, ¬ rk .ref ∈ st .refs, ∀ r. ¬ r ∈ st .refs ⊦

Rule argument

[EXRARG : pos: left 2, [extquanttermlist: (rk .ref)abort:F, discard:F, computed:F]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (rk .ref)]]