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Proof step 5 from proof refs-empty (previous step)

⊦ # ∅ .refs = 0, ∅ .refs = ∅

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ rset = rset0 ↔ (∀ r. r ∈ rset ↔ r ∈ rset0)
Proof step 4:
⊦ # ∅ .refs = 0, ∀ r. r ∈ ∅ .refs ↔ r ∈ ∅

Rule argument

[speclemmaarg: ,rset = rset0 ↔ (∀ r. r ∈ rset ↔ r ∈ rset0) ,[rset0, rset] → [∅, ∅ .refs] ,F ,set-basic ,references ,Extension ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (∅, ∅ .refs)]]