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Proof step 10 from proof refs-put (previous step)

r0 ∈ st .refs ⊦ st .refs = ∅, r0 = r, # st .refs = 0, r0 ∈ st

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

[crewrite-arg: refs-def, F, [st, r] → [st, r0]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, r0)]]