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Proof step 16 from proof refs-put (
previous step
)
rk = r -- sk ⊦ st[rk, val] .refs = st .refs ++ r
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 15
:
⊦ st[r -- sk, val] .refs = st .refs ++ r
Rule argument
[emptyarg]
Additional information
[[CONCRETESIMPRULES : ()]]