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Proof step 55 from proof subset-size (previous step)

¬ r ∈ st1 .refs, st1[r -- sk, val] ⊆ st0, # st0 .refs < # st1 .refs + 1, ∀ st. # st1 .refs ≤ # st .refs ∨ ¬ st1 ⊆ st ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 54:
st1[r -- sk, val] ⊆ st0, # st0 .refs ≤ # st1 .refs, ∀ st. # st1 .refs ≤ # st .refs ∨ ¬ st1 ⊆ st ⊦ r ∈ st1 .refs

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ m + n = n + m], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ ¬ m < n ↔ n ≤ m], [CSIMPSEQ : ⊦ m < n + 1 ↔ ¬ n < m])]]