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Proof step 58 from proof subset-size (previous step)

# st0 .refs < # (st1 .refs ++ rk .ref), st1[rk, val] ⊆ st0, ∀ st. # st1 .refs ≤ # st .refs ∨ ¬ st1 ⊆ st ⊦

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 57:
rk = r -- sk, # st0 .refs < # (st1 .refs ++ r), st1[rk, val] ⊆ st0, ∀ st. # st1 .refs ≤ # st .refs ∨ ¬ st1 ⊆ st ⊦

Rule argument

[speclemmaarg: ,r = rk .ref ∧ sk = rk .key ↔ rk = r -- sk ,[rk, r, sk] → [rk, r, sk] ,T ,refkey , ,elim ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ r = rk .ref ∧ sk = rk .key ↔ rk = r -- sk])], [EXTRATERMS : (rk, r, sk)]]